96=3(2^x+^2)

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Solution for 96=3(2^x+^2) equation: 



96=3(2^x+^2)

We move all terms to the left:

96-(3(2^x+^2))=0



We calculate terms in parentheses: -(3(2^x+^2)), so:

3(2^x+^2)

We multiply parentheses

6x+

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We move all terms containing x to the left, all other terms to the right

-6x=-96

x=-96/-6

x=+16

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